In the given figure, PR is a line segment, a line
segment PQ is parallel to the another line
segment RS and O is the mid-point of QS. Then
prove that
(I) triangle poq is congruent to triangle ros
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Answer:
If you would have given the figure than; it must be more easier to give your answer
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Given : PR is a line segment, a line segment PQ is parallel to the another line segment RS and O is the mid-point of QS.
To find : prove that (I) triangle poq is congruent to triangle ros
Solution:
Comparing Δ POQ & Δ RSO
∠POQ = ∠ROS ( Vertically opposite angles)
OQ = OS as O is the mid point of QS => OQ =OS = QS/2
∠PQO = ∠RSO as PQ ║ RS
=> Δ POQ ≈ Δ RSO ( ASA)
QED
Hence Proved
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