Question

In the given figure, PR is a line segment, a line
segment PQ is parallel to the another line
segment RS and O is the mid-point of QS. Then
prove that
(I) triangle poq is congruent to triangle ros​​

Answer 1

Given :

PQ ║RS

OQ = OS

To prove :

ΔPOQ ≅ ΔROS

Proof :

OQ = OS

∠POQ = ∠ROS (VOA)

∠PQS = ∠QSR (Alt. Int ∠'s)

OQ = OS (Given)

∴ ΔPOQ ≅ ΔROS  ⇒ (ASA Congruency Criterion)

Hope it helped :)

Answer 2

Answer:

in the picture you can see poq and sor are two triangles .

so angle sor = poq as they are reflexive angle

and o being the mid of QS

so so=qo

and pq parallel to Sr and PR is their divider so Angle QPO = SRO

so

QPO = SRO

so=qo

sor = poq

so triangle POQ is congruent to ROS

by the law of A-S- A

please mark as brainliest answer