in the given figure pr is a straight line and the accused stands on it find the value of x also find angle poq and angle pqr ?
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angle poq +angle for=180°
(angle on straight line)
2x -30+3x+40=180°
5x +10=180
5x=170
X=34
so
angle poq= 2x -40=68- 30=38°
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Answer:
angle poq+angle por=180°
2x-30+3x+40=180°
5x+10=180°
5x=170x=34
so,
angle poq=2x-40=68-40=28
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