Question

In the given figure, PR = QR, Angle PRA = Angle QRB and angle BPR = angle AQR.
Prove that BP=QA ​

Answer 1

Answer:

Here,

In ∆s PBR and QRA

PR=QR (given)

<BPR=<AQR (given)

<PRB=<<ARQ(addition of same angles with equal angle will also be equal)

∆PBR ≅ ∆ QRA

Therefore,

PB = AQ ( corresponding sides of equal triangles)

Hence, proved

Answer 2

Answer:

here is your answer I hope It is helpful