in the given figure,prove that :
1-∆acb =∆ecd
2-ab =ed
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Heya,
Answer to your question is:-
In ∆ACB and ∆ECD
AC = EC |given|
ACB = ECD |vertically opposite angles|
BC = DC |given|
∆ACB ≈ ∆ECD |by SAS congurency|
=> AB = ED |by CPCT|
Hence, Proved.
HOPE THIS HELPS YOU:-))
@Ashu
Answer to your question is:-
In ∆ACB and ∆ECD
AC = EC |given|
ACB = ECD |vertically opposite angles|
BC = DC |given|
∆ACB ≈ ∆ECD |by SAS congurency|
=> AB = ED |by CPCT|
Hence, Proved.
HOPE THIS HELPS YOU:-))
@Ashu
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