Question

In the given figure, prove that:
∆A + ∆B + ∆C + ∆D + ∆E + ∆F = 360°
​

Answer 1

Answer:

let ∆ACB and ∆DEF be equilateral triangle

then

A+B+C = 180°

and

D+E+F = 180°

add them both

you will get your answer

hope this will help you

please mark it brainlist

please like it

Answer 2

Answer:

In ABC ,By Angle Sum Property ;

A+B +C = 180° --------(1)

In DEF ,By Angle Sum Property;

D+E +F = 180° ---------(2)

Add equation (1) and (2)A+B +C+D+E +F = 180° + 180°

A+B +C+D+E +F = 360°

Hence Proved