In the given figure prove that
AB+BC+CD+DA > 2 AC
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Step-by-step explanation:
in ∆ABC
We know that sum of 2 side's is always greater then 3rd side
AB+BC>AC.............(1)
similarly in ∆ADC
AD+DC>AC...........(2)
from equation (1) and(2)
=AB+BC+CD+DA>AC+AC
=AB+BC+CD+DA>2AC
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