Question

In the given figure, prove that: ∆ADB = ∆ACB​

Answer 1

Answer:

→Angle ADB=Angle ACB(Given)

→Angle ABD=Angle BAC(Given)

→BA=BA(common)

==

==

HENCE,

→∆ABD=∆BAC=(AAS)

→and AD=BC (From ∆ABD=∆BAC)

Hence proved

Answer 2

in Triangles ADB & ACB;

  angle ADO = Angle BCO  (Given)

  OD = OC

  OA = OB

Therefore, by SAS Congruency rule, triangles ADB and ACB are congruent and are equal in area