Question

in the given figure prove that angle BAE minus angle DCE equal to angle ADC

Answer 1

Please provide the figure if you want the solution

Answer 2

Attached is the missing figure:

The sum of the property is:

∠BAE= ∠AEF + ∠AFE --- (1)

We know that AB and CD are parallel and CE here is transversal and the corresponding angles are equal.

∠AFE = DCE ---(2)

from equation 1 and equation 2 we will be able to derive this:

∠BAE = ∠AEF + ∠DCE

∠BAE - ∠DCE = ∠AEF

∠BAE - ∠DCE = ∠AEC

If there is any confusion please leave a comment below.