in the given figure , prove that BC||ED
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Here is the solution of your asked query:
In ∆ABC and ∆AED, we have;AD=AB∠BAC=∠DAE {Vertically opposite angles}AE=ACSo, ∆ABC≅∆AEDThen by CPCT we have;∠AED=∠ACB and ∠ADE=∠ABCThis means alternate angles are equal which results in BC∥DE
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