Question

in the given figure, prove that EC || ED.​

Answer 1

Answer:

Step-by-step explanation:

In triangle EAD and triangle ABC

EA=AC (given)

BA=AD (given)

Angle BAC = angle EAD (vertically opposite angles)

By SAS rule triangle ACB congruent to triangle AND

angle ACB=angle AED (C.P.C.T)

But these forms a pair of alternate interior angle

So ED parallel to BC