In the given figure, prove that MNO ~ OPQ
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It is given that OA=OB and OP=OQ
By considering the △OAQ and △OPB
Therefore, by SAS congruence criterion
△OAQ=△OPB
We know that the corresponding parts of congruent triangles are equal
So we get
∠OBP=∠OAQ..(1)
Consider △BXQ and △PXA
We can write it as
BQ=OB−OQ and PA=OA−OP
We know that OP=OQ and is given that OA=OB
So we get BQ=PA.(2)
In △BXQ and △PXA
We know that ∠BXQ and ∠PXA are vertically opposite angles
∠BXQ=∠PXA
From (1) and (2) and AAS congruence criterion we get
△BXQ≅△PXA
So we get PX=QX and AX=BX(c.p.c.t).
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