in the given figure prove that triangle xyz is congruent to triangle xpz and yz is equal to pz and angle yxz is equal to angle pxz
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yz = pz & ∠yxz = ∠pxz
Step-by-step explanation:
Comparing Δxyz & Δxpz
xz = xz ( common)
∠xyz = ∠xpz = 90°
xy = xp given
=> Δxyz ≅ Δxpz
=> yz = pz
& ∠yxz = ∠pxz
QED
Proved
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Answer:
this is the answer
Step-by-step explanation:
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