in the given figure prove that x=tikka+bitta+y
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draw a line. through BD
such that,
beta =beta 1+beta 2. ....(1)
and x=x1+x2.........(2)
now,
in Triangle BAD,
using exterior angle property
Beta1+alpha=x1..........(3)
similarly in Triangle BCD,
Beta2+ gamma=x2.........(4)
adding both equations (3) and (4) and using equation (1) and (2);
beta + gamma + alpha=x
such that,
beta =beta 1+beta 2. ....(1)
and x=x1+x2.........(2)
now,
in Triangle BAD,
using exterior angle property
Beta1+alpha=x1..........(3)
similarly in Triangle BCD,
Beta2+ gamma=x2.........(4)
adding both equations (3) and (4) and using equation (1) and (2);
beta + gamma + alpha=x
prateekvishnoip5q5ha:
any confusion?
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