In the given figure, PS 1) Prove that triangle PSQ is congruent to triangle PSR. 2) Is angleRPS is equal to angleQPS? Give Reasons
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Answered by
56
1.
PR=PS (given)
angle PSR=angle PSQ (each of 90°)
PS=PS(common)
Hance ∆PSR is Congurent to ∆PSQ
2.
angle RPS=angle QPS (c.p.c.t)
Hope it helps you :)
PR=PS (given)
angle PSR=angle PSQ (each of 90°)
PS=PS(common)
Hance ∆PSR is Congurent to ∆PSQ
2.
angle RPS=angle QPS (c.p.c.t)
Hope it helps you :)
Answered by
31
IN ∆PRS and ∆PQS,
== angle PRS = angle PQS (angle opposite to equal sides are equal)
== angle PSR = angle PSQ (each 90 °)
== PR = PQ (given)
Therefore ∆PRS and ∆PQS are congruent (AAS)
angle RPS =angle QPS (by C.P.C.T.)
HOPE THIS WILL HELP U
== angle PRS = angle PQS (angle opposite to equal sides are equal)
== angle PSR = angle PSQ (each 90 °)
== PR = PQ (given)
Therefore ∆PRS and ∆PQS are congruent (AAS)
angle RPS =angle QPS (by C.P.C.T.)
HOPE THIS WILL HELP U
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