in the given figure,PS is the bisector of QPR and PT | QR. PRT=60,PQS=60,find SPT
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PT is the bisector of angle QPR in triangle pqr and PS is perpendicular to QR find X and Y when angle pqs with 50 degree
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Answer:
PT perpendicular to QR
=> T = 90⁰
PS is the bisector of QPR
QPS=SPT
in triangle PQT
T+Q+QPT = 180⁰
90⁰+60⁰+QPT = 180⁰
150⁰+QPT = 180⁰
QPT = 180⁰-150⁰
QPT = 30⁰
in triangle PTR
TPR+R+T = 180⁰
TPR +60⁰+90⁰ = 180⁰
TPR+150⁰ = 180⁰
TPR = 180⁰-150⁰
TPR = 30⁰
if two sides of a triangle are 60⁰ then third side is also 60°
QPS+SPT+TPR = 60⁰
SPT+SPT+TPR=60⁰
2×SPT+30⁰=60⁰
2×SPT = 60⁰-30⁰
SPT = 30÷2
SPT = 15⁰
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