Question

In the given figure
PS = SR = RQ and PQ ll SR
If RT ll PS and < RQP = 60°
then prove that
i PS = SR = R1 = PT
ii RT + TQ = 2RQ​

Answer 1

Answer:

I) here it is given that....

And PQ||SR..... ---------- eq. 1

Also it is given that RT || PS---------------- eq.2

From eq. 1 and 2....

we can conclude that....

'PSRT' IS A PARALLELOGRAM.....

hence the opposite sides will be equal....

but PS=SR=RQ=RT....

And hence.....PS = SR = R1 = PT....