In the given figure, PT is tangent and PAB is a
secant to the circle. If the bisector of angle ATB
meets AB at M, then prove that angle ATM is
1/2( Angle PTA - Angle PAT)
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Answer:
As angle PTA = angle PTB ( tangent -angle theorem) (1)
And Angle BTM = angle MTA (given) (2)
And angle PMT = angle PBT + angle MTB
So angle PMT = angle PTA + angle MTA (using (1) and (2) )
And angle PTA + angle MTA = PTM
So angle PMT = angle PTM ( hence proved)
In triangle PMT
We have angle PMT = angle PTM
So PM = PT (isosceles triangle)
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