Question

In the given figure ,PT is the bisector of angel QPR in the triangle PQR and PS perpendicular to are . Find the value of "x"

Answer 1

$\huge\mathbb{A~N~S~W~E~R}$

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In ΔPQR,

30°+50°+angle QPR = 180°

angle QPR = 100°

In ΔPSR,

90° + 30° + angle SPR = 180°

angle SPR = 60°

PT is bisector of angle QPR,

angle TPR = 50°

X + angle TPR = angle SPR

X + 50° = 60°

X = 10°

${\huge\color{Red}{Answer~is~10°}}$

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Answer 2

Answer:

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