Question

In the given figure , PT is the bisector of angle QPR in trianglePQR and PS perpendicular QR . Find the value of x , when angle PQS=50 and angle PRT=30.

Answer 1

Answer:

Step-by-step explanation:

In triangle PSR 30+90+x = 180

X=180-120

= 60

As pt bisects it x= 30 degree

Answer 2

Answer:

Step-by-step explanation:First by linear pair Angle PQS + EXTERIOR ANGLE=180 degree

50+exterior angle=180

exterior angle=130

Angle QPT = 40(angle sum property)

QPT+x=TPR(PT IS BISECTOR OF QPR)

BY EXTERIOR ANGLE PROPERY

130degree=angleQPR+anglePRQ

130=QPT+TPR+PRQ(QPT=TPR)

130=40+x+40+x+30

130=110+2x

2x=20

x=10