In the given figure pt. O is thr centre of the circle. Angle AOC is 135degree. Find arc BC and angle BPC
Answers
Answer:
ANS IS 22.5
Step-by-step explanation:
ANGLE AOC+COB=180
135+ANGLE COB=180
ANGLE COB=180-135=45
X=1/2 ANGLE COB {ANGLE SUBTENDED BY THE CHORD IN THE CENTRE OF THE CIRCLE IS DOUBLE THE ANGLE SUBTENDED BY THE CHORD AT THE CIRCUMFERENCE}
1/2*45=22.5
Given : O is the centre of the circle.
∠AOC = 135°
To Find : arc BC and ∠BPC
Solution:
AOB is straight line
Hence ∠AOC + ∠BOC = 180°
=> 135° + ∠BOC = 180°
=> ∠BOC = 45°
arc BC = 45°
∠BOC = 2 ∠BPC ( angle by same arc BC at center and remaining circle)
=> 2 ∠BPC = 45°
=> ∠BPC = 22.5°
arc BC = 45°
∠BPC = 22.5°
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