in the given figure px and ry are perpendicular to the diagonals qs of a parallelogram pqrs prove that triangle pqs congruent ryq ,px= ry
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I think, the question should be prove that triangle PXS congruent to RYQ
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In ΔPXS and ΔRYQ
PS = QR (opp sides of paralleogram)
angle PXS = angle RYQ = 90 degrees
angle PSX = angle YQR (alternate interior angles)
By AAS two triangles are congruent.
By CPCT PX = RY
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