Question

in the given figure, QA⊥AB and PB⊥AB. If AO=20CM, BO=12CM, PB=18CM, find AQ

Answer 1

Solution:-

Given QA ⊥ AB and PB ⊥ AB so,

∠ QAO = ∠ PBO = 90° ...... (1)

In Δ AOQ and Δ BOP

∠ QAO = ∠ PBO  (from equation 1)

∠ AOQ = ∠ BOP .. (vertically opposite angles)

So,

Δ AOQ is same as Δ BOP .. (by AA rule)

Then we get:

⇒ OAAQ = OBBP

⇒ 20AQ = 1218

⇒ AQ = 20 × 1812

⇒ AQ = 5 × 183  

⇒ AQ = 5 × 6 = 30 cm

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