In the given figure, QA perpendicular toAB and PBperpendicular toAB. If AO=20 cm, BO=12 cm, PB=18 cm find AQ.
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The triangles Δ QAO and ΔPBO are similar.
AQ || BP as AQ ⊥ AB and BP ⊥ AB
AO || OB as AB is a straight line.
QO || PO as PQ is a straight line.
So, AQ / AO = BP / BO
AQ = 18 * 20 / 12 = 30 cm
AQ || BP as AQ ⊥ AB and BP ⊥ AB
AO || OB as AB is a straight line.
QO || PO as PQ is a straight line.
So, AQ / AO = BP / BO
AQ = 18 * 20 / 12 = 30 cm
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