In the given figure,QP || BC and PR || CD.if AQ=3cm,QB=2cm and RD=5cm,then the length of AR is:
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FIGURE IS IN THE ATTACHMENT.
Given:
AP = 2 cm
BQ = 3 cm
RC = 4 cm
AP = AR = 2 cm
BQ = BP =3 cm
RC = CQ = 4 cm
(We know that two tangents drawn from an external point to the circle are equal in length.)
AB = AP + BP = 2 + 3 = 5 cm
BC = BQ + CQ = 3 + 4= 7 cm
CA = CR + AR = 4 +2 = 6 cm
Perimeter of ∆ ABC = AB + BC + CA
Perimeter of ∆ ABC = 5 + 7 + 6 = 18 cm.
Hence, the Perimeter of ∆ ABC = 18 cm.
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