Question

In the given figure, QP = PR, BP = PC, PQ ⊥ AB and PR ⊥ AC. Prove that AB = AC​

Answer 1

Answer:

In triangle BPQ and PRC

QP = PR (given)

BP = PC (given)

angle BQP = angle PRC (90°, given perpendicular)

By SSA congurency rule triangle BQP is congruent to triangle CRP

So QB = RC (By C.P.C.T)

If QB = RC.

So other half will also be same (AQ = RA)

QB + AQ = AR + RC

AB = AC

Proved

Answer 2

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