Question

In the given figure, ΔQPS = ΔSRQ. Find each value.
(a) x
(b) ∠PQS
(c) ∠PSR
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Answer 1

Answer:

Angle R = 106° (opposite angle of ||gram are equal)

106° = 2x + 12

106° - 12 = 2x

94° = 2x

x = 94/2

x = 47°

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Let angle S be y.

We know that sum of interior angles of a ∆ = 180°

then,

106° + 42° + y = 180°

148° + y = 180°

y = 180° - 148°

y = 32°

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