In the given figure, ΔQPS = ΔSRQ. Find each value.
(a) x
(b) ∠PQS
(c) ∠PSR
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Answered by
12
Answer:
Answer:
Angle R = 106° (opposite angle of ||gram are equal)
106° = 2x + 12
106° - 12 = 2x
94° = 2x
x = 94/2
x = 47°
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Let angle S be y.
We know that sum of interior angles of a ∆ = 180°
then,
106° + 42° + y = 180°
148° + y = 180°
y = 180° - 148°
y = 32°
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Answered by
4
Answer:
Step-by-step explanation:
x=
2x+12=106
2x=106-12
2x=94
x=94/2
x=47
PQS= 106+42+pqs=180
pqs=180-148
pqs=32
psr=psq+rsq
42+32=psr
=psr=74
hope it is correct
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