Question

In the given figure QR is a common tangent of the given circle touching at T meets QR at P . If PT = 3.8cm then find the length of QR(in cm)
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Answer 1

$\huge\underline\mathfrak\pink{αղsաҽɾ} </p><p>$

lҽղցԵհs օբ Եհҽ ԵαղցҽղԵs ժɾαաղ բɾօต αղ ҽxԵҽɾղαl թօíղԵ Եօ α cíɾclҽ αɾҽ ҽզմαl. 

∴զթ=թԵ=3.8cต............(í)

թɾ=թԵ=3.8cต............(íí)

բɾօต ҽզմαԵíօղs (í) αղժ (íí):

զթ=թɾ=3.8cต

ճմԵ, զɾ=զթ+թɾ

∴զɾ=3.8+3.8

զɾ=7.6cต

Answer 2

Answer:

Lengths of the tangents drawn from an external point to a circle are equal.

∴QP=PT=3.8cm............(i)

PR=PT=3.8cm............(ii)

From equations (i) and (ii):

QP=PR=3.8cm

But, QR=QP+PR

∴QR=3.8+3.8

QR=7.6cm