Question

In the given figure. QS is a tangent to the circle OS = 8 cm,OQ=6 CM then the length of QS is​

Answer 1

Answer:

We know that the shortest distance between the radius and the tangent to a circle is a perpendicular;

Therefore Angle OQS = 90 degrees

Or,

Triangle OQS is A right angled triangle, therefore OS² = OQ²  +  QS² (pythagoras theorem)

Putting the respective values , we get;

8² = 6² + QS²

=> 64 - 36 = OQ²

=> 28 = OQ²

=> OQ = 2√7 cm

Hope this helps