In the given figure, quadrilateral PQRS is such that
PQ = PS and PR bisects ∠QPS.
Show that ∆PQR ≅ ∆PSR.
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Answered by
24
Answer:
Step-by-step explanation:
given: i)PQ = PS
ii)∠QPR=∠SPR
TPT: ∆PQR ≅ ∆PSR
Solution: In ∆PQR and ∆PSR
i) PQ = PS ------------(given)
ii) ∠QPR=∠SPR ------------(given)
iii) PR=PR ------------(common side)
∴ ∆PQR ≅ ∆PSR by SAS.
Answered by
13
Answer:
Construction- Join QS and center point name as O
Proof-In ∆PQR and ∆PSR
PR=PR (common)
PQ=PS(given)
<QPR=<SPR(By construction)
∆PQR≅∆PSR(By S.A.S criteria of congruence)----proved
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