Question

In the given figure, radius of a
circle is 1472 cm. PQRS is a
square. EFGH, ABCD, WXYZ and
LMNO are four identical squares.
What is the total area (in cm.) of
all the small squares ?​

Answer 1

Answer:

To find : area of small circles

Step-by-step explanation:

PR = QS = Diameter = 2 * 14√2 = 28√2 cm

PR² = PQ² + QR²     ( PQ = QR)

=> PQ = QR = RS = PS = 28 cm

Let say side of small square = x

in rectangle  sides are   28 + x + x    &  x

Here diagonal again = Diameter = 28√2

=> (28 + 2x)² + x² = (28√2)²

=> 28² + 4x²  + 112x + x²   = 2 * 28²

=> 5x²  + 112x  - 28² = 0

=>  5x²  + 140x - 28x - 28² = 0

=> 5x(x + 28) - 28(x + 28) = 0

=> (5x - 28)(x + 28) = 0

=> x = 28/5

=> x = 5.6

Area of one small square =  (5.6)² =  31.36 cm²

Area of 4 small square =  4 *31.36  = 125.44 cm²

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