Question

In the given figure radius of the circle is 5 cm. Chords AB

and CD are parallel and distance between them is 7 cm. If

CD = 6 cm, then find AB.​

Answer 1

Answer:

Step-by-step explanation:

Take a circle, draw two parallel chords ab and cd on the opposite side of the center.

Take point p on ab and point q on on cd.

Centre = o. Join co and ao. These co and ao are radii r= 5cm (given).

In triangle coq

Co =5,cq =3 (cq=1/2of cd,),

By pythagorus theorem

Co^2=cq^2+oq^2

Oq^2=16,oq=4

Since we know the total distance between the chords is 7cm

Therefore op=(7-4=3)

Now in triangle aop ao^2=op^2+ap^2

Where ao =rafius =5(given) and op =(7-4=3)

Ap^2=16,ap=4

Since ap=1/2ab

Ab =2ap =2*4=8

Length of chord ab =8cm

Answer 2

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