In the given figure ray AZ bisect angel BAD and angle DCB: a) Prove that the triangle BAC = triangle DAC b) Is AB = AD? c) Is CD = CB?
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Step-by-step explanation:
a) Angle DAC = Angle BAC (Given in the figure)
AC = AC (Common Side)
Angle DCA = Angle BCA (Given in the figure)
With the help of above description we can say that, ∆BAC is congruent to ∆DAC by ASA (Angle-side-Angle) Property.
b) Yes, since ∆BAC is congruent to ∆DAC, AB = AD and CD = CB.
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