Question

In the given figure, ray AZ bisects ∠DAB & ∠DCB. Then, the pairs of corresponding parts such that ∆DAC ≅∆BAC are:​
long answer
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Answer 1

Answer:

$< bac = < dac \\ < bca = < dca \\ ac = ac \\ therefore \: \: \:$

triangle DAC similar by triangle BAC

that's is your answer