In the given figure, rays OA,OB,OC and OD are such that angle AOB= 56° angle BOC=100°,angle COD=x° and angle DOA = 74°
find the value of x.
: sum of all the angles around a point is 360°.......
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Answer:
i have drawn a figure after reading your question.
and I have find the value of x°
as it is given that sum of all the angles around a point is 360° .
so with help of that , we get value of x°
x° = 130°
HOPE THIS HELPS
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