Question

In the given figure, rays OA,OB,OC and OD are such that angle AOB= 56° angle BOC=100°,angle COD=x° and angle DOA = 74°
find the value of x.
: sum of all the angles around a point is 360°

Answer 1

let angle COD be x
x+100*+56*+74*=360*(by A.S.P.T)
x+220*=360*
x=360*-220*
x=140*
Hence,
angle COD=140*

Answer 2

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