Question

In the given figure, RQ is tangent to the circle with center O. If SQ = 6cm and QR =4cm, then OR find

Answer 1

5, because OR is twice SR and SR=10 by Pythagoras theorem.
therefore OR =5

Answer 2

sq=6cm = oq=3cm

qr=4cm , since rq is a tangent to the circle at q

angle rqo=90 {tangent is perpendicular to the radius of a circle

in triangle rqo, {pythagores theorem}

or^2 = qr^2 + oq^2

or^2 = 4^2 + 3^2

or^2 = 25

or = 5cm