Question

in the given figure S is a point on the side QR of triangle pqr prove that PQ + QR + PR is greater than 2 PS​

Answer 1

as we know that the sum of two sides is always greater than the third side. in triangle pqs, pq+qs>ps and in triangle psr, pr+sr>ps adding the above two equations, we get pq+pr+rq>2ps hence,proved.
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Answer 2

Answer:

the given figure, S is a point on the side QR of triangle PQR . Prove that PQ + QR + PR > 2FS