Question

In the given figure Seg AF|| Seg BC Seg AB is Congruent to Seg AC then prove that Seg AF is the bisector of Angle EAR ? ​

Answer 1

Answer:

hey!

Step-by-step explanation:

actually i think the question is prove that af is bisector of eac and not ear

we know that seg ab = seg ac

let ∠abc = 1

then ∠abc = ∠acb = 1(angles oppostie to equal sides of a Δ are equal

given : af║bc

∴∠eaf=∠abc = 1 (corresponding angles)

now using exterior angle property,

∠abc+∠acb = ∠eac

but

∠eac =∠eaf+∠fac

⇒∠1+∠1 = ∠1+∠fac

∴∠fac  = ∠1

since ∠eaf = ∠fac = ∠1

af bisects angle ∠eac

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:)