Question

In the given figure seg BE ⊥ seg AB and seg BA ⊥
seg AD
if BE= 6 and AD = 9
find A (∆ABE)/A(∆BAD)​

Answer 1

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Answer 2

Given :- In the given figure seg BE ⊥ seg AB and seg BA ⊥ seg AD if BE= 6 and AD = 9 .

To Find :- A(∆ABE) / A(∆BAD) = ?

Solution :-

we know that,

• Area of ∆ = (1/2) * Base * perpendicular height .

so,

→ A(∆ABE) = (1/2) * AB * BE = (1/2) * AB * 6 = 3AB unit²

and,

→ A(∆BAD) = (1/2) * AB * AD = (1/2) * AB * 9 = (9/2)AB unit²

then,

→ A(∆ABE) / A(∆BAD) = 3AB/(9/2)AB = 3 / (9/2) = 3 * (2/9) = 2/3 (Ans.)

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