In the given figure, SEG qs perpendicular to side pr, SEG rt perpendicular to side pq, p_s_r and p_t_q. Show that (1) triangle pqs similar to triangle prt (2) qs×tp =ps×rt
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Step-by-step explanation:
Show the two triangles similar by aa similarity test
Angle p =angle p. Common angle
Angle t= angle s. Each 90
Now,qs x tp=ps x rt. Csst
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