in the given figure show that AB , EF.
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140 +40=180 So , CD II EF(adjacent angles) and 35 +45 =75 So AB I| EF Then AB also ॥ CD
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Angle ABC =Angle BCD (Alternate interior angles)
AB // CD
Angle ECD + Angle FEC =180 degree (Cointerior angles)
EF // CD
AB // CD
EF // CD
So,AB // EF.
AB // CD
Angle ECD + Angle FEC =180 degree (Cointerior angles)
EF // CD
AB // CD
EF // CD
So,AB // EF.
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