In the given figure show that
AB II EF
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Angle BCD= angleBCE+angleDCE
=25+35=60
Angle ABC =angleBCD
But these are alternate angles
ThereforeAB||CD————1
Now,
Angle FEC +angleDCE=145+35=180
The adjacent angles are supplementary.
Therefore, CD||EF————-2
Using 1 and 2
AB||EF
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