in the given figure, show that AD=BC
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Given that AD∣∣BC
⇒∠DAC=∠BCA corresponding angles of parallel lines
Considering the triangles ΔABC and ΔCDA
AD=BC .....Given
∠DAC=∠BCA .....proved above
AC=AC .....Common Side
So by SAS congruency
ΔABC ≅ ΔCDA
Corresponding sides and angles of congruent triangles are also equal.
⇒ AB=DC
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mst
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