In the given figure, show that AD = BC
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In ΔAOD & ΔBOC
In ΔAOD & ΔBOC OA=OB (given)
In ΔAOD & ΔBOC OA=OB (given) OD=OC (given)
In ΔAOD & ΔBOC OA=OB (given) OD=OC (given)∠AOD=∠BOC ( vertically opposite angles )
ΔAOD≅ΔBOC (by SAS condition of congruency )
ΔAOD≅ΔBOC (by SAS condition of congruency ) ⟹AD=BC (corresponding parts of congruent triangles are equal)
ΔAOD≅ΔBOC (by SAS condition of congruency ) ⟹AD=BC (corresponding parts of congruent triangles are equal) Hence , it is proved.
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