Question

In the given figure Show that ∆EFG = ∆EHG also is EF = EH Give reason ​

Answer 1

Answer:

In EHF and EHG

EF=EG(given)

EHF=EHG=90(EH perpendicular FG)

EH=EH (common)

EHF=~ EHG

EFH=EGH

F=G