Question

in the given figure, side ba of∆abc has been produced to d such that cd=ca and side cb has been produced to e. if angle bac=106°and angle abe =128° , find angle bcd.​

Answer 1

Answer:

angle CAB = 106°

angle CAD = 180° - 106° ( linear pair )

angle CAD = 74°

angle CDA = angle CAD = 74° ( angle on the same sides are equal )

angle ABC = 180° - 128° (angle ABE) (linear pair)

angle ABC = 52°

angle CAB + angle ABC + angle ACB = 106° + 52° + angle ACB = 180° ( Angle Sum Property )

angle ACB = 180° - 158°

angle ACB = 22°

angle CAD + angle CDA + angle ACD = 180° (angle sum property)

74° + 74° + angle ACD = 180°

angle ACD = 180° - 148° = 32°.

angle ACD + angle ACB = angle BCD

32° + 22° = angle BCD

54° = angle BCD

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Answer 2

Answer:

Answer is Given in the picture