In the given figure side BC of A ABC is bisected at D and O is any point on A
ed at D and O is any point on AD. BO and CO
at E and F respectively and AD produced to x so that D is the midpoint
FOX. prove that AO:AX=AF:AB and show that EF//BC.
Answers
Answered by
2
Answer:
- please give the figure
Answered by
1
Answer
in triangle ABX
af /fb =ao/bx { by bpt } .....(1)
similarly in triangle ACX
ad/ox=ae/ec { by bpt }.......(2)
from(1) and (2) we get
ae/fb =ae/ec
so by bpt converse
ef||bc
from adding (1) on both sides we get
ax/oa = fb /af
hence proved
Attachments:
Similar questions