Question

In the given figure, side BC of ∆ABC has been produced to a point D. If ∠A= 3y°, ∠B = x°, ∠ACB= 5y° and ∠ACD = 7y°. Then, the value of x is

Answer 1

Answer:

x = 4y°

Step-by-step explanation:

Angle A = 3y°

Angle B = x°

Angle ACB = Angle C = 5y°

Angle ACD = 7y°

Angle ACD = Angle A + Angle B

7y ° =3y ° + Angle B

Angle B = 7y° - 3y°

Angle B = 4y°

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